C63 Torque/HP Curves
06-20-2011, 12:48 PM
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06-20-2011, 03:02 PM
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this is 4th gear pull (dont mind the higher numbers thats was with my old PC tune, the low number is stock)
this is 5th gear pull as you can see the limiter was there and car dint get to go all out. (again the high number was with PC tune and low was with stock)
this is 5th gear pull as you can see the limiter was there and car dint get to go all out. (again the high number was with PC tune and low was with stock)
06-20-2011, 05:32 PM
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'11 C63, '22 GLS 63, Porsches, M3, M4
That's a heck of a flat torque curve. Interesting though that the acceleration when driving feels much stronger at 4500 versus 2500 rpm - any idea why?
Also, does anyone have the torque and power curves at the crankshaft?
Also, does anyone have the torque and power curves at the crankshaft?
Last edited by IAA-C63; 06-20-2011 at 10:09 PM.
06-20-2011, 09:58 PM
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'11 C63 w/ P31
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06-20-2011, 10:30 PM
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'11 C63 w/ P31
Also top speed is controlled by aero dynamics and gearing as well.
06-20-2011, 11:21 PM
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'11 C63, '22 GLS 63, Porsches, M3, M4
That is false....horsepower is a function of torque x revs. There is an exact formula, I don't know it. How do u think a ferrari, m3, s2000 or F1 car accelerate so quickly with minimal torque , high HP and high revs.
Also top speed is controlled by aero dynamics and gearing as well.
Also top speed is controlled by aero dynamics and gearing as well.
a = T G / m R, where a is acceleration, T is engine torque, G is overall gear ratio, m is car mass, and R is wheel/tire radius.
I gather that those other cars make up for lack of low to mid rev torque by staying at high revs.
I agree with your comments on top speed.
Clarification: One could think of hp as the ability to generate acceleration at a given speed, since P = F v (where P is power, F is force, and v is velocity), and a = F / m. That means that potential acceleration is inversely related to speed, and top speed is reached when acceleration drops to zero. My original question assumes that the speed (and gear) is the same when comparing acceleration from 2500 versus 4500 rpm. If the torque is about the same at both revs, the acceleration should also be about the same, but it doesn't feel that way. Either my feeling is wrong or there's something else going on which I'm not accounting for (which seems more likely).
Last edited by IAA-C63; 06-21-2011 at 12:23 PM.
09-20-2012, 10:29 PM
#10
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Yes, hp = torque x rpm / 5252. But acceleration is still basically proportional to torque, not hp. Here's the formula, neglecting drivetrain losses and other losses:
a = T G / m R, where a is acceleration, T is engine torque, G is overall gear ratio, m is car mass, and R is wheel/tire radius.
I gather that those other cars make up for lack of low to mid rev torque by staying at high revs.
I agree with your comments on top speed.
Clarification: One could think of hp as the ability to generate acceleration at a given speed, since P = F v (where P is power, F is force, and v is velocity), and a = F / m. That means that potential acceleration is inversely related to speed, and top speed is reached when acceleration drops to zero. My original question assumes that the speed (and gear) is the same when comparing acceleration from 2500 versus 4500 rpm. If the torque is about the same at both revs, the acceleration should also be about the same, but it doesn't feel that way. Either my feeling is wrong or there's something else going on which I'm not accounting for (which seems more likely).
a = T G / m R, where a is acceleration, T is engine torque, G is overall gear ratio, m is car mass, and R is wheel/tire radius.
I gather that those other cars make up for lack of low to mid rev torque by staying at high revs.
I agree with your comments on top speed.
Clarification: One could think of hp as the ability to generate acceleration at a given speed, since P = F v (where P is power, F is force, and v is velocity), and a = F / m. That means that potential acceleration is inversely related to speed, and top speed is reached when acceleration drops to zero. My original question assumes that the speed (and gear) is the same when comparing acceleration from 2500 versus 4500 rpm. If the torque is about the same at both revs, the acceleration should also be about the same, but it doesn't feel that way. Either my feeling is wrong or there's something else going on which I'm not accounting for (which seems more likely).
