Interior LED's?
Last edited by KhangT; Aug 14, 2010 at 12:34 AM. Reason: forgot pics
13.5 volts, 100 ohms = 135 mA
W= E*I
13.5 Volts * .135 A = 1.822 Watts (electrical/thermal)
You can get away with a 100 ohm 2 watt resistor
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If you could double the resistor value to ~200 ohms the resistor wattage could be cut in half to a 1 watt unit.
It all depends upon what the minimum current the bulb checking circuit needs to see to be happy.
Does anyone know what is the bulb style for the under-door puddle lights? I would like to go with a high intensity white LED for the under-door lighting.
I also am changing out the marker lights and DRL bulbs with high intensity white (no blue stuff here). I have factory installed HID's so I do not need pretend blue lights outside the car.
I also ordered the license tag LED lights.
Question: Is there an additional, unused light holder in the front headlight assemblies? I see that there is a black rubber cap covering some spot where a bulb could go.
My factory foglights are futzed up. I bought a replacement set after I ran over an "alligator" (chunk of truck tire) that knocked the passenger side foglight out of the fixture where it was lost on the road.
BTW, if you ever lose your outdoor temperature sensor and the air conditioning will not hold temperature control very well it may have taken out that temperature sensor attached to the passenger side foglight (looks like a black pitot tube attached to the foglight fixture.
The Best of Mercedes & AMG
My car is at the body shop being fixed after a truck tire smashed the front of it.
I will post it when I get the car back.




13.5 volts, 100 ohms = 135 mA
W= E*I
13.5 Volts * .135 A = 1.822 Watts (electrical/thermal)
You can get away with a 100 ohm 2 watt resistor
-----------
If you could double the resistor value to ~200 ohms the resistor wattage could be cut in half to a 1 watt unit.
It all depends upon what the minimum current the bulb checking circuit needs to see to be happy.
P = VI
Power required to satisfy the computer = 5W
V = 12V (Standard car battery)
Therefore I = P/V = 5/12 = 0.4167amps
V = RI --> R = V/I = 12/0.4167 = 28.78 ohms.
Therefore resistor needed = 28.78 ohms or greater, 5W
Why would you want to use a 100ohm resistor that can only handle 2W, when the required wattage to satisfy the computer is 5W??
Also the 100ohms will draw way more current than say a 30ohm resistor thereby adding unnecessary load on the battery.
Where do you get 13.5V from?
Why do you assume the resistor to be 100ohms right at the start. the goal is to find the resistance required....not the Power.
Do you know how much heat a 200ohm 1W resistor would produce when loaded with a 12V load??? Especially considering it wouldnt even shut the compuer up because it will consume only upto 1 W. Also would reduce its life.
I believe the 13.5V is the voltage from the alternator, which is probably the value that should be used.




Based on 13.5V:
I = P/V = 5/13.5 = 0.3704 amps
R = V/I = 13.5/0.3704 = 36.44 ohms
However I use a 35ohm 5W resistor for my LED city lights and my LED license plate lights and they work perfectly...no flickering, no errors. Technically this shouldnt work if the threshold is 36.44 ohms (based on 13.5 V)
Im sure 36.44 ohms would work as well, but as I mentioned earlier, the higher the resistance, the more the current drain (and heat generated). So why go higher when 35 ohms will work just as well?
I would think the power rating is based off the alternator voltage because that's the voltage the vehicle is primarily under when the car is started.
That 36.44 ohm is going to be your total impedance. You would have to also include the resistance caused by the led's. So with your 35ohm resistor and the internal resistance of the led, along with the computer's range of error(my assumption) your setup works fine.
Keep in mind this is all speculation, I have not run any tests on this but it's just my thought. I agree with you that 100 ohms is pointless and if the values inputted were correct i would stick with 35-40ohm range.




I would think the power rating is based off the alternator voltage because that's the voltage the vehicle is primarily under when the car is started.
That 36.44 ohm is going to be your total impedance. You would have to also include the resistance caused by the led's. So with your 35ohm resistor and the internal resistance of the led, along with the computer's range of error(my assumption) your setup works fine.
Keep in mind this is all speculation, I have not run any tests on this but it's just my thought. I agree with you that 100 ohms is pointless and if the values inputted were correct i would stick with 35-40ohm range.
This makes sense.




I'm not going to drive around with them on

Was just thinking it'd be cool for the entrance and exits

I was only thinking of doing blacklights for the dome lights only.
So the map lights and any other light used for actual... well... use... I was planning on getting the ones posted here by the OP.
If anyone finds any, PM me the link/post it here please





Was just thinking it'd be cool for the entrance and exits

I was only thinking of doing blacklights for the dome lights only.
So the map lights and any other light used for actual... well... use... I was planning on getting the ones posted here by the OP.
If anyone finds any, PM me the link/post it here please

Those lights can make even the slightest stain very very visible.
PM user advans...he did a blacklight interior when he had his coupe.




I might just ditch my resistors and buy these. Its hard to find LED's that are bright enough to illuminate the entire plate.
Gynecologist MD, can you post a link to the place you bought these from?



