Limited Slip Diff avail. from AMG
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Limited Slip Diff avail. from AMG
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E55, F550, S600 Ducati 999
AMG "upgrades" your differential and transmission software at the factory, but the price is cheap compared to the tuners. Brabus and Vath both do LSD conversions for the car for 4990 euro and 4500 euro respectively. You also have the option of a ratio change as well. I'm sure MKB probably offers something, but they never answer sales enquiries. Their service is shocking, it is a surprise they manage to stay in business..
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E55
I am a little surprized that E 55 does not have limited slip differential. How then does traction control work?
When a car starts slipping the only thing that can happen in a sotck E 55 is differential application of brakes and reduction of engine torque. Is htis correct.
Would this imply that limited slip diff will enhance performance a lot?
When a car starts slipping the only thing that can happen in a sotck E 55 is differential application of brakes and reduction of engine torque. Is htis correct.
Would this imply that limited slip diff will enhance performance a lot?
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one of seven
so.......is it positraction (both rear wheels driven equally & locked together)? In other words, when you burn rubber from a standstill do you get 1 wheel smokin' or 2??
I'm ordering my 2004 E55 tomorrow, just curious.
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I'm ordering my 2004 E55 tomorrow, just curious.
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E55, F550, S600 Ducati 999
As far as I am aware, there is no positraction or limited slip capability at all. With no interference power will generally transmit to the wheel with least traction, the opposite of what you actually want. Having said that, the electronic traction control operates by braking the spinning wheel and reducing power if necessary.
#9
I am a bit confused by this. Please help me out. If I turn off the traction controll on my 211 E55 and land on the gas hard it will liquify both rear tires as long as I feel like wasting good new rubber and carve two nice black strips into the ground. If it does not have some kind of limited slip wouldn't it nove to one wheel. If the traction controll was involved wouldn't it brake the wheels down to a stop?
I know the TC is never really off and it can not defy gravity once the wheels get really spinning but it seems like sime type of limited slip is in play here.
Thanks!
I know the TC is never really off and it can not defy gravity once the wheels get really spinning but it seems like sime type of limited slip is in play here.
Thanks!
#10
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Originally posted by NewBlack55
If I turn off the traction controll on my 211 E55 and land on the gas hard it will liquify both rear tires as long as I feel like wasting good new rubber and carve two nice black strips into the ground.
If I turn off the traction controll on my 211 E55 and land on the gas hard it will liquify both rear tires as long as I feel like wasting good new rubber and carve two nice black strips into the ground.
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I am a bit confused now. In theory without LSD, if one wheel slips completely as on ice, the car will not travel. Under traction control the wheel will be braked. Whihc should mean the car will neither travel nor will the wheels travel. In other words we should have something like being in neutral.
Is this so.
Is this so.
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2003 E55,2005 Ferrari F430 Spider, 2005 Corvette 427 TT, 2005 Range Rover
If the spinning wheel is braked, the other wheel propels the car. Based on my experience with this car, on the street there is no need for any additional limited slip above whatever is already implemented. Even when getting the rear planted on corner exits, both wheels seem to break away pretty evenly.
#13
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if one of the wheels is braked, that wheel is seeing some resistance, and for an open diff, the power will transfer to the wheel that isn't braked
going completely straight, there is no difference in torque between the two wheels, so both should light up just fine. When turning, there is still power going through both wheels. even if one is moving faster than the other, but they still both have resistance. In the case where there is no resistance to a wheel, then there's the problem
going completely straight, there is no difference in torque between the two wheels, so both should light up just fine. When turning, there is still power going through both wheels. even if one is moving faster than the other, but they still both have resistance. In the case where there is no resistance to a wheel, then there's the problem