Effect of Wheel Mass on Acceleration
------------------ Summary -----------------
A 1 lb weight reduction in the wheel/tire combo will net you a total of about 1.7 lbs saved (.7lb rotational). The absolute maximum total savings would be 2lbs, if all weight saved was ideally at the tire OD. A critical assumption is there is no change in the tire OD.
So the rule is 1.7 lbs net saving for each lb saved in the wheel/tire combo.
------------------ Analysis --------------------
The laws of physics rule here. Energy is needed to bring the wheel/tire mass up to speed (mph) and to spin it to the related rpm. Consider a lighter tire/wheel combo:
m = mass reduction
I = inertia reduction
w = rotational speed
v = car speed
r = tire radius
E = total energy saved by mass reduction "m"
^2 = squared
E = 1/2 m v^2 + 1/2 I w^2
E = E(speed) + E(rotation)
Rotary Inertia is the sum of each bit of mass times it's radius squared. If all the mass reduction is at the tire OD (the theoretical but not practical limit), the inertia reduction is the maximum possible value:
I = r^2 m
The relation between car speed and tire rpm:
v = r w
Combine 3 equations above:
E = 1/2 m v^2 + 1/2 (r^2 m) (v/r)^2
E = 1/2 m v^2 + 1/2 (m) (v)^2
E = 2 x E(speed) ... the 2X limit
So if you drop 10 lbs per corner, the net total weight savings is 4 x 17 = 68 lbs. For a 3700 lb car and driver, that's only a 1.8% change.
The main benefit of reducing wheel/tire or any unsprung weight is handling and comfort, by increasing the tires ability to keep good contact with the road. Total unsprung weight might be 80 lbs per corner, and 10 lbs would be a 13% change ... very significant.
-------------------------------------------------
If just a 17" or 18" wheel is 10 lb lighter (reuse same tires), then the total net savings is about 13 lbs. The rotational part is 3 lbs.
.
Last edited by kevink2; Mar 27, 2010 at 02:56 AM.
------------------ Summary -----------------
A 1 lb weight reduction in the wheel/tire combo will net you a total of about 1.7 lbs saved (.7lb rotational). The absolute maximum total savings would be 2lbs, if all weight saved was ideally at the tire OD. A critical assumption is there is no change in the tire OD.
So the rule is 1.7 lbs net saving for each lb saved in the wheel/tire combo.
------------------ Analysis --------------------
The laws of physics rule here. Energy is needed to bring the wheel/tire mass up to speed (mph) and to spin it to the related rpm. Consider a lighter tire/wheel combo:
m = mass reduction
I = inertia reduction
w = rotational speed
v = car speed
r = tire radius
E = total energy saved by mass reduction "m"
^2 = squared
E = 1/2 m v^2 + 1/2 I w^2
E = E(speed) + E(rotation)
Rotary Inertia is the sum of each bit of mass times it's radius squared. If all the mass reduction is at the tire OD (the theoretical but not practical limit), the inertia reduction is the maximum possible value:
I = r^2 m
The relation between car speed and tire rpm:
v = r w
Combine 3 equations above:
E = 1/2 m v^2 + 1/2 (r^2 m) (v/r)^2
E = 1/2 m v^2 + 1/2 (m) (v)^2
E = 2 x E(speed) ... the 2X limit
So if you drop 10 lbs per corner, the net total weight savings is 4 x 17 = 68 lbs. For a 3700 lb car and driver, that's only a 1.8% change.
The main benefit of reducing wheel/tire or any unsprung weight is handling and comfort, by increasing the tires ability to keep good contact with the road. Total unsprung weight might be 80 lbs per corner, and 10 lbs would be a 13% change ... very significant.
-------------------------------------------------
If just a 17" or 18" wheel is 10 lb lighter (reuse same tires), then the total net savings is about 13 lbs. The rotational part is 3 lbs.
.
This is more than evident when doing chassis dyno tests. I've seen differences of 30HP (indicated) just by changing tire and wheels -- and this was only on a 450HP vehicle. This doesn't mean the engine gained 30HP, but the driveline losses were significantly reduced by going to a smaller/lighter assembly ONLY.
For low-powered street cars (14+ second 1/4 mile capability), the gain may be as little as you have described -- or even less. For high-powered cars or racing cars, the difference can be 5x or more greater. You must take in to account the energy require to spin up each of the four tire/wheel assemblies at the initial rate of angular acceleration and then at the new rate. It is a dynamic set of equations that requires integration as there are few constants. Since time is involved and can't be ignored.
Chris
Last edited by Chris_B; Mar 26, 2010 at 12:52 PM.
Mr Martinez used the force-mass-acceleration method to evaluate the effect at audiworld:
http://www.audiworld.com/tech/wheel13.shtml
He came to the same conclusion. The acceleration variable dropped out in the analysis.
For your dyno run, I'm sure there was no big difference in the time to accelerate the different wheels. The hp difference you measured could be due to traction differences, and or different load loss due to hysterysis (heat loss).
Mr Martinez used the force-mass-acceleration method to evaluate the effect at audiworld:
http://www.audiworld.com/tech/wheel13.shtml
He came to the same conclusion. The acceleration variable dropped out in the analysis.
For your dyno run, I'm sure there was no big difference in the time to accelerate the different wheels. The hp difference you measured could be due to traction differences, and or different load loss due to hysterysis (heat loss).
Time cannot be factored out of the time equation (essentially an energy balance), just the torque equations. Take a quarter mile time, for example. You can't say that the kinetic energy of the car (plus the rotational energy of the on-board components) is the same if the car has a higher trap speed (higher velocity) after modification. In fact, you will find that the car usually burns more fuel after you have lightened it. Why? Not because there is less mass to haul down the track, but because higher speeds were reached. Time matters because velocity matters. It can only be factored out if you are not interested in distance, which is clearly not the case with motor vehicles.
Mr. Martinez's calculations ignore the energy balance, which is necessary to provide a real-world prediction. His equations, while factually correct, are written for a specific time slice and apply only instantaneously, not integrated over the whole acceleration event. That integration certainly takes time into account and, since angular acceleration is a squared term, the more change you make -- well, the more change you make!
I've been involved in this type of vehicle improvement for over 20 years as an engineer and tuner. I can say without hesitation that reducing rotating weight can make huge difference, even more if it is unsprung (although those benefits are different). I also know from both physics and from actual track testing that the more power on hand, the more difference the changes make. For a 6,000 lb. S-Class, don't expect much. But the quicker the car, the greater the positive effect of removing rotating weight. A small change on a top fuel dragster can make a significant difference in trap speed.
Chris
http://www.stealth316.com/2-calc-hp-et-mph.htm
Torque = I x (ang acc'n), Force = Mass x Acc'n
I trust your experience a lot more than your knowledge of physics. Among other things, I did fully build an SCCA DP race engine, busting the rules by adding and tunning triple DCOE's to the I6. I can use a wrench, as well as an FEA program.
Last edited by kevink2; Mar 28, 2010 at 01:22 AM.
Modified magazine did a test and found.........probably none at all:
http://www.modified.com/tech/modp-09...est/index.html
A 17.4# Volk RE30 and 18.4# SSR Type-F both had slower times than a 20.3# AME TM02 and a 20.8# 5Zigen FN01R-C (same tire, driver, track, and day).
I am curious if anyone has done any real-world tests of their own.
if a large percentage of the mass is further from the center of rotation it will have a more significant effect.
light weight wheels are great for performance but, heavier wheels tend to offer more comfort and small sharp impacts are easier for the suspension manage as the heavier wheel will react slower. This dynamic is one reason AMG wheels are typically not very light
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The equation for angular kinetic energy: E(rot) = 1/2 * I(rot) x w^2
Where:
E = angular rotational energy
I = rotational mass moment of intertia
w = angular velocity
Not that I go to Wikipedia for my physics, but this one is just too easy:
http://en.wikipedia.org/wiki/Rotational_energy
Congratulations on your accomplishments!
The Best of Mercedes & AMG
Modified magazine did a test and found.........probably none at all:
http://www.modified.com/tech/modp-09...est/index.html
A 17.4# Volk RE30 and 18.4# SSR Type-F both had slower times than a 20.3# AME TM02 and a 20.8# 5Zigen FN01R-C (same tire, driver, track, and day).
I am curious if anyone has done any real-world tests of their own.
I have been involved in real-world testing. Some of those results were believable and some weren't, depending on conditions, repeatability, method of data collection, etc. The ones I've been involved with were for companies doing product development, so they are not public. The results almost always indicated lighter is better and less rotational inertia is better. Whether or not a change can be justified for a particular budget, well, that is a bit more subjective!
Chris
"That integration certainly takes time into account and, since angular acceleration is a squared term, the more change you make -- well, the more change you make!"
I'm still waiting to see your eq'n with (ang acc'n)-squared .

flywheel data
WT, Inertia -meas'd-
20.0 1.068 (OEM)
17.5 .733 (NEW)
Hed 3 Bike Wheel and Reviews
I designed it about 15 years ago and it's still Lance Armsrong's choise in TDF time-trials.
.
Last edited by kevink2; Mar 29, 2010 at 10:48 PM.
Last edited by kevink2; Mar 30, 2010 at 10:59 PM.
No one there argues about the benefits of lighter wheels whether in climbing the Alp d'Huez or a sprint finish.
Modified magazine did a test and found.........probably none at all:
http://www.modified.com/tech/modp-09...est/index.html
A 17.4# Volk RE30 and 18.4# SSR Type-F both had slower times than a 20.3# AME TM02 and a 20.8# 5Zigen FN01R-C (same tire, driver, track, and day).
Great article on wheel fabrication. But the most significant test result for me was this:
"As the tires heated up after just one cold run, the change in rolling resistance was more than the difference between all the wheels."
Tires with innefficient structural designs will generate more heat, and may have more rolling resistance under load.






