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Solved my lack of low end power

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Old Feb 10, 2011 | 02:38 AM
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W203E35's Avatar
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Solved my lack of low end power

Hey Guys,

I think I solved my lack of low end power. The painting of the volks have been put on a hold until I change out my bushing and finish suspension work. I put my stock wheels on and today was the first day I gave it a pedal to the metal from a stop. I feel a significant difference.

I figured out my stock diameter is 24.7 and the aftermarket wheel diamater is
25.3 = .6 inches. I mean half an inch should be a significant difference to feel right?

I believe they are both the same weight...if not very close.

Only way to figure out is Irwindale. Whose coming to Irwindale next Thursday??
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Old Feb 10, 2011 | 03:29 AM
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But your aftermarket are wider right? Youre using more power to get all the wheels to rotate, you have more contact area to move.

Little experiment, place one finger a counter and push it, it's pretty easy to move it forward right? now put all your fingers on the counter and try doing the same thing, it takes more effort to move it. Its the same with your wheels. Didnt feel like thinking of a better experiment to do lol
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Old Feb 10, 2011 | 04:53 AM
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Thanks that makes perfect sense.
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Old Feb 10, 2011 | 05:00 AM
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its all about rolling resistance. i felt the same when I had my cls wheels to my new wheels. Car feels like it accelerates better. They're just as wide but my circumfence is lower and my tires are not as wide.
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Old Feb 10, 2011 | 05:07 AM
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Damn, I feel bad for milkman (C230 NA) who has a straightpipe with 19x9.5 running 285/30/19!!! or was is 275 eighter way. No wonder he complains about power. He's got those SL wheels too so I'm sure their pretty heavy too.
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Old Feb 10, 2011 | 09:07 AM
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From: fort worth, tx
06 C230 SS 6spd
yeah factory wheels are pretty heavy. I'm glad my new wheels are forged. Depending on the car maker they use different companies to do their wheels. On subaru they use enkei for the factory wheels then go up to bbs for the sti models.
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Old Feb 10, 2011 | 02:36 PM
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Hey Karo,

I don't think that 0.6in more is causing the lack of power you're feeling....

GIVEN:

Inertia Resistance (IR):



where:

IR = inertia resistance [N]
m = car mass + equivalent mass of rotating parts [kg]
a = car acceleration [m/s2]
mcar = car mass [kg]
meq = equivalent mass of rotating parts [kg]
= [ Iw (1/rw)^2 + Ip hf (if /rw)^2 + Ie ht (if ig / rw)^2]

where:

Iw = polar moment of inertia of wheels and axles ≈ 2.7 [kg m2]
Ip = polar moment of inertia of propeller shaft ≈ 0.05 [kg m2]
Ie = polar moment of inertia of engine ≈ 0.2 [kg/m2] + polar moment of inertia of flywheel and clutch ≈ 0.5 [kg m2]
hf = mechanical efficiency of final drive
ht = mechanical efficiency of transmission system (hg x hf)
ig = gearbox reduction ratio [ig1 or ig2 or ………….]
if = final drive reduction ratio
rw = tire radius [m]

* ( + ), (+) with the car in acceleration. {tractive resistance}
(-) with the car in deceleration. {tractive effort}

----

if the wheels actually do weigh the same...

and if rw increases by 0.6in
aftermarket - stock --> (25.3 - 24.7 = 0.6in)
(or 25.3/24.7*100 = 2.43% increase)

then the equivalent mass of rotating parts actually decreases with (1/rw)^2

meq = [ Iw (1/rw)^2 + Ip hf (if /rw)^2 + Ie ht (if ig / rw)^2]
= (1/rw)^2 [Iw + Ip hf (if)^2) + Ie ht (if ig)^2)]

as rw increases, (1/rw)^2 decreases
after some math, it goes down by 4.69%

therefore, you actually have less rotational inertia or resistance from the wheels by almost 5%

unless i totally goofed something

Last edited by Midnight Koop; Feb 10, 2011 at 03:10 PM.
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Old Feb 10, 2011 | 02:40 PM
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Old Feb 10, 2011 | 02:46 PM
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I work with that guy... and he's mean.
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Old Feb 10, 2011 | 02:55 PM
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Thanks for all the input guys.

Originally Posted by midnight kompre
Hey Karo,

I don't think that 0.6in more is causing the lack of power you're feeling....

GIVEN:

Inertia Resistance (IR):



where:

IR = inertia resistance [N]
m = car mass + equivalent mass of rotating parts [kg]
a = car acceleration [m/s2]
mcar = car mass [kg]
meq = equivalent mass of rotating parts [kg]
= [ Iw (1/rw)^2 + Ip hf (if /rw)^2 + Ie ht (if ig / rw)^2]

where:

Iw = polar moment of inertia of wheels and axles ≈ 2.7 [kg m2]
Ip = polar moment of inertia of propeller shaft ≈ 0.05 [kg m2]
Ie = polar moment of inertia of engine ≈ 0.2 [kg/m2] + polar moment of inertia of flywheel and clutch ≈ 0.5 [kg m2]
hf = mechanical efficiency of final drive
ht = mechanical efficiency of transmission system (hg x hf)
ig = gearbox reduction ratio [ig1 or ig2 or ………….]
if = final drive reduction ratio
rw = tire radius [m]

* ( + ), (+) with the car in acceleration. {tractive resistance}
(-) with the car in deceleration. {tractive effort}

----

if the wheels actually do weigh the same...

and if rw increases by 0.6in
aftermarket - stock --> (25.3 - 24.7 = 0.6in)
(or 25.3/24.7*100 = 2.43% increase)

then the equivalent mass of rotating parts actually decreases with (1/rw)^2

meq = [ Iw (1/rw)^2 + Ip hf (if /rw)^2 + Ie ht (if ig / rw)^2]
= (1/rw)^2 [Iw + Ip hf (if)^2) + Ie ht (if ig)^2)]

as rw increases, (1/rw)^2 decreases
after some math, it goes down by 4.69%

therefore, you actually have less rotational inertia or resistance from the wheels by almost %5

unless i totally goofed something
Are you sure you didn't come up with the E=MC2??

So what you're saying is I'm feeling a placebo effect?
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Old Feb 10, 2011 | 03:05 PM
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Originally Posted by mskembo
I work with that guy... and he's mean.
with me?
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Old Feb 10, 2011 | 03:07 PM
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Originally Posted by Karo
Thanks for all the input guys.



Are you sure you didn't come up with the E=MC2??

So what you're saying is I'm feeling a placebo effect?
possibly... i'm no expert... but i'm just following the math and it seems to say that if anything, you should have an advantage.

do you know the exact weight of both wheels (stock and aftermarket)?
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Old Feb 10, 2011 | 03:08 PM
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Originally Posted by Karo
Thanks for all the input guys.



Are you sure you didn't come up with the E=MC2??

So what you're saying is I'm feeling a placebo effect?
Quite certainly lol
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Old Feb 10, 2011 | 03:33 PM
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How the hell are you going to post all those formulas and then follow it up with "I'm no expert."

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Old Feb 10, 2011 | 03:38 PM
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Originally Posted by LILBENZ230
How the hell are you going to post all those formulas and then follow it up with "I'm no expert."

i was thinking the same..
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Old Feb 11, 2011 | 02:37 AM
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I'm more of the belief that the rolling diameter change mostly affected your net gear ratios. A smaller tire gives you an effectively lower gear ratio.

I'd work out the change numerically, but my head still hurts from that inertia bit above.
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Old Feb 11, 2011 | 02:54 AM
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Originally Posted by Karo
..Who's coming to Irwindale next Thursday??
Is that tomorrow or next week? Might have to knock off work early.

edit: almost certain it'll beat up on a mildly-modified G35/37

Last edited by splinter; Feb 11, 2011 at 03:34 AM.
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Old Feb 11, 2011 | 07:38 AM
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Originally Posted by LILBENZ230
How the hell are you going to post all those formulas and then follow it up with "I'm no expert."

only because i didn't derive the forumlas, i only rearranged them to isolate variables and plugged in values to get an estimate. i get bored at work sometimes, so this is my outlet

Originally Posted by lkfoster
I'm more of the belief that the rolling diameter change mostly affected your net gear ratios. A smaller tire gives you an effectively lower gear ratio.

I'd work out the change numerically, but my head still hurts from that inertia bit above.
i think if gear ratio and tire diameter were correlated, then they wouldn't be listed as independent variables in the formula...

Last edited by Midnight Koop; Feb 11, 2011 at 07:40 AM.
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Old Feb 11, 2011 | 09:03 AM
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I'm too lazy to work out the numbers so I found this link instead.

http://www.ausfish.com.au/vforum/arc.../t-148715.html
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Old Feb 11, 2011 | 11:50 AM
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Karo its all about the look
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Old Feb 11, 2011 | 12:19 PM
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How abou the COF? its much higher with wider wheels...by looking at the formulas its not present...
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Old Feb 11, 2011 | 01:07 PM
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Wait... dont you have Kleemann headers on your car?
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Old Feb 11, 2011 | 03:44 PM
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he has the knockoffs I think
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Old Feb 11, 2011 | 04:52 PM
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Hey Splinter, that's next week.

No not Kleemann, OBX . Over 6 months and they are still great. Definitely a Kleemann replica. I would recommend them....actually I have and many w204 guys have asked me about them. I think people keep their OBX headers down low because of the brand

OK, so the aftermarket wheels (not weighed but lifted to compare) feel a little heavier.

Only way to really know is at the race track.
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Old Feb 11, 2011 | 05:01 PM
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I bet you COF=coefficient of friction plays a good part too along with heavier wheels
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