Significant Change in Range Estimates




I have typically been driving in local traffic, occasionally on the highway for a short period of time in southern Florida. Temps have been in mid 70’s to low 80’s. I recently charged up to 95% and made a round trip to Orlando and back traveling on I 95 and the Florida turnpike averaging 75 mph. I did about 300 miles round trip. Before I started the trip the range estimate the car was reporting was 403 miles at 100% SOC. Now I know that is very generous, but now after the trip my range estimate at 100% is 327 miles, the lowest I’ve seen since I’ve had the car in Florida. I’m confused, because the recent consumer report article stated the EQS 580 sedan range was significantly better than 327 miles on the highway at 70 mph. I wouldn’t have though range dropped that much. Any thoughts?
I have typically been driving in local traffic, occasionally on the highway for a short period of time in southern Florida. Temps have been in mid 70’s to low 80’s. I recently charged up to 95% and made a round trip to Orlando and back traveling on I 95 and the Florida turnpike averaging 75 mph. I did about 300 miles round trip. Before I started the trip the range estimate the car was reporting was 403 miles at 100% SOC. Now I know that is very generous, but now after the trip my range estimate at 100% is 327 miles, the lowest I’ve seen since I’ve had the car in Florida. I’m confused, because the recent consumer report article stated the EQS 580 sedan range was significantly better than 327 miles on the highway at 70 mph. I wouldn’t have though range dropped that much. Any thoughts?
I have typically been driving in local traffic, occasionally on the highway for a short period of time in southern Florida. Temps have been in mid 70’s to low 80’s. I recently charged up to 95% and made a round trip to Orlando and back traveling on I 95 and the Florida turnpike averaging 75 mph. I did about 300 miles round trip. Before I started the trip the range estimate the car was reporting was 403 miles at 100% SOC. Now I know that is very generous, but now after the trip my range estimate at 100% is 327 miles, the lowest I’ve seen since I’ve had the car in Florida. I’m confused, because the recent consumer report article stated the EQS 580 sedan range was significantly better than 327 miles on the highway at 70 mph. I wouldn’t have though range dropped that much. Any thoughts?
Although irritating, try the trip at 65-70MPH next time and see what you get








I have typically been driving in local traffic, occasionally on the highway for a short period of time in southern Florida. Temps have been in mid 70’s to low 80’s. I recently charged up to 95% and made a round trip to Orlando and back traveling on I 95 and the Florida turnpike averaging 75 mph. I did about 300 miles round trip. Before I started the trip the range estimate the car was reporting was 403 miles at 100% SOC. Now I know that is very generous, but now after the trip my range estimate at 100% is 327 miles, the lowest I’ve seen since I’ve had the car in Florida. I’m confused, because the recent consumer report article stated the EQS 580 sedan range was significantly better than 327 miles on the highway at 70 mph. I wouldn’t have though range dropped that much. Any thoughts?
Thus, assuming no change in elevation, if you travel at 75 mph you would use about 15% more electrical power than when you travel at 65 mph.
Furthermore, it is easy, for example, to calculate the additional power required for an EV to climb a hill/mountain. (=total weight *9.8*elevation gain/time, not counting rolling resistance). There is not a lot of wasted energy.
Energy is equal to the amount of work done. E=W
The work done is equal to force F times the distance D that the force is applied. W=K1*F*D
The aero drag force Fad is proportional to the velocity V squared. Fad=K2*V^2
Therefore:
1. E=K1*K2*V^2*D
Let:
a) K=K1*K2
b) B (the battery capacity) = E
c) R = the range
Substituting a, b, c above into 1.
2. B=K*V^2*R
Or
3. R= 1/K*B/(V^2)
Having said the above, the range is more complicated in that I think that the mechanical losses tend to be proportional to speed and the HVAC losses are related to the time traveled. So in the case of HVAC the consumption of range actually decreases with speed (well sort of because heat transfer does increase with speed)
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3. R= 1/K*B/(V^2)
Having said the above, the range is more complicated in that I think that the mechanical losses tend to be proportional to speed and the HVAC losses are related to the time traveled. So in the case of HVAC the consumption of range actually decreases with speed (well sort of because heat transfer does increase with speed)
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Last edited by MBNUT1; Dec 19, 2023 at 11:20 AM.
Have a look at these calculations: https://physics.stackexchange.com/qu...air-resistance
It concludes that almost all of the opposing force on the vehicle is air drag.
Applying the drag force equation 1/2*rho*Cd*A*V^2 at 70 MPH results in 0.135 kWh of consumption per mile. Consumer Reports test at 70 MPH resulted in a range of ~380 miles. Given the 108 kWh battery this is a total consumption rate of 0.284 kWh/mile so the aero drag was about half of that.
Applying the drag force equation 1/2*rho*Cd*A*V^2 at 70 MPH results in 0.135 kWh of consumption per mile. Consumer Reports test at 70 MPH resulted in a range of ~380 miles. Given the 108 kWh battery this is a total consumption rate of 0.284 kWh/mile so the aero drag was about half of that.









